if one zero of 3xsquare -8x+2k+1 is seven times the other , find k
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Answered by
7
3 x^2 - 8 x + 2 k + 1
Let one zero be p
other zero is 7p
sum of zeroes = 8/3
p + 7p = 8/3
8p = 8/3
p= 1/3
Product of zeroes = 2k +1)/ 3
p( 7 p) = 2 k +1)/ 3
1/3 ( 7/3) = 2 k +1)/ 3
7/3 = 2 k + 1
2 k= 7/3 - 1
2k = 4/3
k= 2/3
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Answered by
2
p(x) = 3x² - 8x + 2k + 1
Let the one zero of p(x) be alpha (a).
Therefore, the other zero is 7 alpha (7a).
Now,
Sum of zeroes = - b/a
a + 7a = - (-8)/3
8a = 8/3
a = 1/3
Also,
Products of the zeroes = c/a
a × 7a = 2k+1/3
7a² = 2k+1/3
7(1/3) = 2k+1/3
7 = 2k+1
2k = 7-1
k = 6/2
k =3
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