Question

If one zero of 4x2-8kx-9is negative of the other, find k

Answer 1

let a zero be £ then another zero will be -£
let a be an constant
thus
a(x-£)(x+£) =4x²-8kx-9
ax²-a£² = 4x²-8kx-9
on comparing both side
one side coefficient of X is zero
and other side coefficient is 8k
thus 8k= 0
k= 0

Answer 2

Step-by-step explanation:

Answer :-

→ k = 0 .

Step-by-step explanation :- ----

It is given that,

→ One zeros of the given polynomial is negative of the other .

Let one zero of the given polynomial be x .

Then, the other zero is -x .

•°• Sum of zeros = x + ( - x ) = 0 .

But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .

==> 2k = 0 .

==> k = 0/2 .

•°• k = 0 .

Hence, it is solved.