if one zero of a polynomial (a2+9)x +13x +6a is reciprocal of the other,find the value of a.
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a is equal to x square
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Now now, || Be prepared to feel the fun:-
---------------> You say the zeroes are Reciprocal [ HEHE 0 = 1/0 ]
----> Btw, => α and 1/α are the zeroes...
===> By Coefficient -- Zero Relation or Viete's Relation:
=========> Product of Zeroes = Constant term / Coeff(x²)
======> a² + 9 = 6a
------------> (a-3)² = 0 ====> a = 3;
You got it a = 3; ||
In case, you liked the response, and at least laughed hehe, mark brainliest
---------------> You say the zeroes are Reciprocal [ HEHE 0 = 1/0 ]
----> Btw, => α and 1/α are the zeroes...
===> By Coefficient -- Zero Relation or Viete's Relation:
=========> Product of Zeroes = Constant term / Coeff(x²)
======> a² + 9 = 6a
------------> (a-3)² = 0 ====> a = 3;
You got it a = 3; ||
In case, you liked the response, and at least laughed hehe, mark brainliest
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