Math, asked by aadibhagat8327, 1 year ago

If one zero of a polynomial is x²+(3-√2)x-3√2 is √2, then find the other zero.

Answers

Answered by ravi34287
21
x^2+(3-root2) x3-root2 
=x^2+3x-root2x3-root2 
=x (x+3)-root2 (x+3) 
=(x-root2)(x+3) 
x=root2; x=_3. 
Other zeros of -3.
Answered by gopikarevathi200687
2

Answer:

Step-by-step explanation:

x^2+(3-root2) x3-root2  

=x^2+3x-root2x3-root2  

=x (x+3)-root2 (x+3)  

=(x-root2)(x+3)  

x=root2; x=_3.  

Other zeros of -3.

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