If one zero of a polynomial is x²+(3-√2)x-3√2 is √2, then find the other zero.
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Answered by
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x^2+(3-root2) x3-root2
=x^2+3x-root2x3-root2
=x (x+3)-root2 (x+3)
=(x-root2)(x+3)
x=root2; x=_3.
Other zeros of -3.
=x^2+3x-root2x3-root2
=x (x+3)-root2 (x+3)
=(x-root2)(x+3)
x=root2; x=_3.
Other zeros of -3.
Answered by
2
Answer:
Step-by-step explanation:
x^2+(3-root2) x3-root2
=x^2+3x-root2x3-root2
=x (x+3)-root2 (x+3)
=(x-root2)(x+3)
x=root2; x=_3.
Other zeros of -3.
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