If one zero of a polynomial (k-1)x + kx +1 is -3 then find the value of k
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2
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ANSWER
Given −3 is the zero of the polynomial (k−1)x
2
+kx+1
So −3 must satisfy the equation (k−1)x
2
+kx+1=0
⟹(k−1)(−3)
2
+k(−3)+1=0
⟹9(k−1)−3k+1=0
⟹9k−9−3k+1=0
⟹6k=8
⟹k=
3
4
Answered by
3
Step-by-step explanation:
ok see it us coming small images
but answer is 34
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