Question

If one zero of a quadratic polynomial f(x)=4xsquare -8kx-9 is negative of the other, find the value of k.

Answer 1

Let the zeroes of the polynomial be
$\alpha \: and \: - \alpha$
So sum of zeroes =-b/a
$\alpha - \alpha = 8k \div 4$
K=0

Answer 2

Answer :- ----

→ k = 0 .

Step-by-step explanation :-

It is given that,

→ One zeros of the given polynomial is negative of the other .

Let one zero of the given polynomial be x .

Then, the other zero is -x .

•°• Sum of zeros = x + ( - x ) = 0 .

But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .

==> 2k = 0 .

==> k = 0/2 .

•°• k = 0 .

Hence, it is solved.