Question

If one zero of a quadratic polynomial x2+(a+1)x-6 is 2,then find the value of a.

Answer 1

I hope this will help you

Answer 2

P(x)=x²+(a+1)x-6

P(2)=(2)²+(a+1)2-6=0

=4+2a+2-6=0

=6+2a-6=0

=2a=0

=a=0