Question

if one zero of p(x) = 3x2 -2k+1 is alpha and other is 7 times alpha find the zeros and value of k

Answer 1

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Step-by-step explanation:

p(x)=3x²-2k+1

zeroes=α,7α

sum of zeroes= - b/a

α+7α= -(2k/3)

8α=2k/3

8α×3=2k

24∝=2k

k=12∝                     (1)

product of zeroes= c/a

∝×7∝=1/3

7∝²=1/3

∝²=1/(3×7)

∝²=1/21

∝=±1/√21

∵∝=±1/√21

∴k=12(±1/√21)

k = ±12/√21