Question

if one zero of p(x) = 4x^2 -( 8k^2-40k)x-9 is negative of the other ,find the value of k.

Answer 1

Hi ,

p( x ) = 4x² - ( 8k² - 40k ) x - 9

compare p( x ) with ax² + bx + c ,

a = 4 , b = - ( 8k² - 40k ) , c = -9

Let m and ( - m ) are two zeroes of p ( x )

we know the relation between zeroes of p( x )

and coefficients of p( x ) ,

sum of the zeroes = - b / a

m - m = - [ - ( 8k² - 40k ) ] / 4

0 = 8k² - 40k

8k ( k - 5 ) = 0

Therefore ,

k = 0 or k - 5 = 0

k = 0 or k = 5

I hope this helps you.

:)

Answer 2

Answer:

Step-by-step explanation:

Hope this will you