Question

If one zero of p(x)=4x²-(8k²-40k)x-9 is negative of the other , find values of k.​

Answer 1

Answer:

let the first zero be "a"

and second zero be "-a"

sum of two zeroes =-b/a

a+(-a) =(8k^3-40k)

0=2k^2-10k

2k(k-5) =0

2k=0 k-5=0

k=0 k=5

hence k=0 or 5

Answer 2

Answer:

Hey Buddy here's ur answer