Question

if one zero of p(x)=4x2-(8k2-40k)x-9 is negative of the other find the value of k​

Answer 1

Answer:

Step-by-step explanation:

ALTAF11 Maths AryaBhatta

Given :-

p ( x ) = 4x² - ( 8k² - 40k )x - 9

Let the zeros be a and -a

then ,

Sum of zeros =  

\frac{ - coeff \: of \: x}{coeff \: of \: {x}^{2} }  

a \: + ( - a) = \frac{ (8 {k}^{2} - 40k) }{4}  

0 = \frac{8 {k}^{2} - 40k }{4}  

0 = 8k² - 40k

0 = k² - 5k

0 = k ( k - 5 )

k = 0

k = 5

Answer 2

Answer

k = 0, 5

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