If one zero of polynomial 2x^2-3x+p is 3 then find the other root(zero).Also find the value of p
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Answer:
The other zero of the given polynomial is -3/2.
Step-by-step explanation:
Here, the given polynomial is,
2x^2-3x+p2x
2
−3x+p
Let, f(x) = 2x^2-3x+pf(x)=2x
2
−3x+p
Given,
3 is a zero of f(x),
⇒ f(3) = 0
\implies 2(3)^2-3(3)+p=0⟹2(3)
2
−3(3)+p=0
\implies 18-9+p = 0\implies p = -9⟹18−9+p=0⟹p=−9
Thus, the polynomial will be,
f(x) = 2x^2-3x-9f(x)=2x
2
−3x−9
=2x^2-6x+3x-9=2x(x-3)+3(x-3)=(2x+3)(x-3)=2x
2
−6x+3x−9=2x(x−3)+3(x−3)=(2x+3)(x−3)
When f(x) = 0
(2x+3)(x-3) = 0 ⇒ 2x+3 = 0 ⇒ x =-3/2
Thus, the other zero of the given polynomial is -3/2.
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