Question

If one zero of polynomial 2x^2 - 5 x - (2 X + 1 )is twice the other, find both of zeroes of the polynomial and the value of k.​

Answer 1

Step-by-step explanation:

will u thank me if i answer

Answer 2

QUESTION:

If one zero of polynomial 2x^2 - 5 x - (2 X + 1 )is twice the other, find both of zeroes of the polynomial and the value of k.

ANSWER:

polynomial :

$2 {x}^{2} - 5x - (2x + 1)$

let one zero of the polynomial be

$\alpha$

then according to the question other zero of the polynomial will be

$2 \alpha$

now we know that;

$sum \: of \: zeroes = \frac{ - coefficient \: of \: x}{coefficient \: of \: {x}^{2} } = \frac{ - b}{a}$

now come to main question;

$2 {x}^{2} - 5x - 2x - 1 \\ 2 {x}^{2} - 7x - 1$

in the given polynomial;

b = -7

a = 2

putting the value in the formula;

$\alpha + 2 \alpha = \frac{ - 7}{2} \\ 3 \alpha = \frac{ - 7}{2} \\ \alpha = \frac{ - 7}{2} \div 3 \\ \alpha = \frac{ - 7}{6}$

one zero of the polynomial is -7/6

then the zero of the polynomial be = -7/6 ×2

= -7/3

plz Mark as brainliest