if one zero of polynomial 3 x cube minus 8 x + 2 k + 1 is 7 times the other find the value of k
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let one of the zero is A then another zero is 7A
now by sum of zeros
7A +A = 8/3
therefore A =1/3
now by product of zeroes
7A^2 = 2k/3
7×1/9 =2k/3 (by putting the value of A)
therefore A =7/6
now by sum of zeros
7A +A = 8/3
therefore A =1/3
now by product of zeroes
7A^2 = 2k/3
7×1/9 =2k/3 (by putting the value of A)
therefore A =7/6
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