Question

if one zero of polynomial 3 x square - 8 x - 2 k + 1 is 7 times the other find both zeros of the polynomial and find the value of k​

Answer 1

Answer:

Step-by-step explanation:

3x²-8x+2k+1

a=3, b=-8 ,c=-2k+1

suppose the zeroes of the equation are α and β . by the given

condition

α=7β

as we know ,

α+β=-b/a

7β+β=-(-8)/3

8β=8/3

β=8/3×1/8=1/3

αβ=c/a

7β×β=-2k+1/3

7×1/3×1/3=-2k+1/3

7/9=-2k+1/3

21/9=-2k+1

21/9-1=-2k

12/9=-2k

4/3=-2k

4/6=-k

-2/3=k

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