if one zero of polynomial 3x2-8x-(2k+1) is seven times the other find both zeroes and value of k ...this is question of class 10th ..plz try to solve it as soon as possible it's urgent.i will definitely mark u as brainlist.
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Step-by-step explanation:
Let the zeroes of the eq. be m,n
Let n=7m
Standard equation of quadratic equation is : ax²+bx+c
-b/a = sum of zeroes
c/a = product if zeroes
Here , a=3,b= -8,c= -(2k+1)
m+n = m+7m = 8m = -(-8)/3 = 8/3
Therefore m = 1/3
n = 7/3
mn = 7/3 × 1/3 = 7/9 = -(2k+1)/3
7/9 = -2k-1/3
7×3/9 = -2k-1
7/3 = -2k-1
7/3 + 1 = -2k
10/3 = -2k
Therefore k = 10/-6 = -5/3
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