Question

if one zero of polynomial 3x²=8x+2k+1is seven times the other, then find all the zeroes of the polynomial.​

Answer 1

pls mrk as brainliest

Answer 2

Answer: P(x)= 3x²=8x+2k+1

a=3       3x²-8x+2k+1=0

b=-8

c=2k+1

Zeroes= a and 7a

α+ β=-b/a

7a+a=-8/3

8a=-8/3

a=-1/3

αβ=c/a

7aXa=2k+1/3

7X1/3X1/3=2k+1/3

7/9=2k+1/3

21/9=2k+1

7/3=2k+1

2k+1=7/3

2k=7/3-1

2k=4/3

k=2/3

Pls mark brainliest!!!