Question

if one zero of polynomial 9 x square + 13x + 6a is reciprocal of the other then a is equal to​

Answer 1

◇given ◇

if one zero of polynomial 9 x square + 13x + 6a is reciprocal of the other then a is equal to

♧solution ♧

Then, the other zero is 1/α . product of zeros = ( α × 1/α ) = 1 . But, product of zeros = ( constant term )/( coefficient of x² ) = 6a/(a² + 9 ) . 6a/(a² + 9) = 1 .

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