Question

if one zero of polynomial (a2+9)x2+13x+6a is reciprcal of the other then find the value of a

Answer 1

Hey there

_____________
The correct answer is;
If one of the zero is reciprocal of the other, 
let one zero be α
other zero will be 1/α

Product of roots = c/a
⇒ α × 1/α = 6a/(a²+9)
⇒ 1 = 6a/(a²+9)
⇒ a² + 9 = 6a
⇒ a² - 6a + 9 = 0
⇒ a² - 3a - 3a + 9= 0
⇒ a(a-3) -3(a-3) = 0
⇒ (a-3)(a-3) = 0
⇒ (a-3)²= 0
⇒ a = 3

Value of a is 3.

Read more on Brainly.in - https://brainly.in/question/193997#readmore

________________________
Hope this helps you
By jerman

Answer 2

Hope it helps you...
If u have any doubt, comment below