Question

If one zero of polynomial (a2+9)x2+13x+6a is reciprocal of the other find the value of a

Answer 1

Step-by-step explanation:

xy=1

c/a =1

6a/(a²+9)=1

6a=a²+9

a²-6a+9=0

(a-3)(a+3)=0

thus

a=3 or a=-3

Thus value of a is either 3 or -3.