Question

if one zero of polynomial f (x)=kx^2-14x+8 is 6 timesof other find the value of K​

Answer 1

Given polynomial =

f(x) = kx²-14x+8

Also it is given that one of the zero is 6 times the another.

Let one zero = α

Let the second zero = 6α

So , we know the relationship between the constant term and the product of Zeroes. Using this relationship we have :

$\alpha \times 6 \alpha = \frac{8}{k} \\ \\ 6 { \alpha }^{2} = \frac{8}{k} \\ \\ k = \frac{8}{6 { \alpha }^{2} }$