Question

If one zero of polynomial is (-2) then find the value of p from p(x) = 2x^2 + px + 3.​

Answer 1

Answer:

p = 11/2

Step-by-step explanation:

2x² + px + 3 = 0

2*(-2)² + p(-2) + 3 = 0

8 -2p + 3 = 0

-2p = -11

p = 11/2

Answer 2

Answer:

p=11/2

Step-by-step explanation:

p(x) = 2x^2 + px +3

One zero of the polynomial= -2

So, p(-2)= 0

therefore, 2*(-2)^2 + p*(-2) +3 =0

or, 2*4 - 2p +3 =0

or, 8+3 - 2p = 0

or, 2p = 11

or, p= 11/2