if one zero of polynomial (k^2=k)x^2+68x+6k is reciprocal of other, Find K
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Hola Anushkaaa,
→ p( x ) = ( k² + k )x² + 68x + 6k
Since, one zero is reciprocal of other, product of zeroes = 1
But, Product of Zeroes = 6k ÷ ( k² + k )
=> [ 6 ÷ ( k + 1 ) ] = 1
=> ( k + 1 ) = 6
=> k = 5
→ p( x ) = ( k² + k )x² + 68x + 6k
Since, one zero is reciprocal of other, product of zeroes = 1
But, Product of Zeroes = 6k ÷ ( k² + k )
=> [ 6 ÷ ( k + 1 ) ] = 1
=> ( k + 1 ) = 6
=> k = 5
anu5hka12:
well the ans for this is given as 5, anyways thanks
Then.. the question you typed above is to blame =_=
Anyway, nice to know that you learnt how it works
Anyway, nice to know that you learnt how it works
I did some changes to meet your expectation.. Hope it helps :p
6k ÷ ( k² + k ) it is +
Yeah Edited :v: Thanks
welcome
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