If one zero of polynomial kx²+10x+k is -1/3 ,then k is
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Answer:
p(x)=kx²+10x+k
x=-1/3
p(-1/3)=0
k(-1/3)²+10(-1/3)+k=0
k/9-10/3+k=0
10k/9=10/3
k=10/3 x 9/10
k=3
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