Question

If one zero of polynomial p (x)=ax3-6x2+11x-6 is 4 than find the value of a

Answer 1

solution:

Here one zero is given=4

so, a(4)^3 -6(4)^2+ 11(4) - 6=0

=> 64a - 96 + 44 - 6= 0

=> 64a - 58= 0

=> 64a=58

=> a= 58/64

=> a= 0.96

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hope it helps☺☺☺

Answer 2

Given one zero is 4 i.e. x=4
So
a(4)^3-6(4)^2+11x4-6
64a-96+44-6=0
64a-102+44=0
64a-58=0
64a=58
a=29/32