If one zero of polynomial x^2-5x-2k+1 is twice the other. Find both the zeroes and also find k............answer fast pls
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let one zero be x
then other is 2x
compare x^2-5x-2k+1 with ax^2+bx+c
we get
a=1,b=-5,c=-2k+1
now
x+2x=-b/a
3x=-5
x=-5/3
and
x×2x=-2k+1
2x^2=-2k+1
2×(-5/3)^2=-2k+1
2×(25/9)=-2k+1
50/9+1=-2k+1
59/9=-2k
k=-59/18
i am not sure about this please recheck it
hope it help u
then other is 2x
compare x^2-5x-2k+1 with ax^2+bx+c
we get
a=1,b=-5,c=-2k+1
now
x+2x=-b/a
3x=-5
x=-5/3
and
x×2x=-2k+1
2x^2=-2k+1
2×(-5/3)^2=-2k+1
2×(25/9)=-2k+1
50/9+1=-2k+1
59/9=-2k
k=-59/18
i am not sure about this please recheck it
hope it help u
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