Question

If one zero of polynomial x square - 8 x + k exceed the other by 2 then find k

Answer 1

Solution:'

given by:-

one zero = 2

$p(x) = {x}^{2} - 8x + k \\ p(2) = 4 - 8 \times 2 + k \\ k = 12 \\ then \: eqution \: is \: \\ {x}^{2} - 8x + 12 \\ \alpha + \beta = - \frac{b}{a} \\ \beta = \frac{8}{1} - 2 \\ \beta = 6 \\ \\( \alpha = 2 \\ \beta = 6) \\ ans$