Question

If one zero of polynomial X2+3x+Kis -3. Then value of k is +

Answer 1

Answer:

The value of K=0

hope it helps you✌

Answer 2

This can be solved by two methods.

Follow the method which is clear for you.

Method 1:

Since, - 3 is a root of the given polynomial, it satisfies the equation when it is placed in place of x.

=> $(-3)^2$ $+ 3(-3) + K = 0$

=> 9 - 9 + K = 0

=> K = 0

Method 2:

You may know the concept that if α and β are the roots of an equation $ax^2 + bx + c$

then,  α + β = -b/a {sum of the roots}

and α*β = c/a {product of the roots}

Given one root is -3.

Let the other root be p

So,

p + (-3) = -3 {here b = 3 and a = 1}

=> p = 0

so, 0 is the root of the equation.

Now,

p * (-3) = K {product of roots}

p = 0

=> K = 0

Comment if you have any further doubts in this question.