if one zero of quadratic polynomial 2 x square - 3 k + 1 x minus 9 is negative of other the find value of k
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1
Answer:
−
3
1
Let p(x)=2x
2
−(3k+1)x−9
Let α,β be the roots of this polynomial.
We know that
α+β=
2
3k+1
= Sum of the roots
αβ=
2
−9
= Products of the roots
Given that : One zero is negative of the other
⇒α=−β
⇒α+β=0
⇒α+β=
2
3k+1
=0
⇒3k+1=0
⇒k=−
3
1
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