Question

if one zero of quadratic polynomial 2x^2-(3k+1)x-9 is negative of the other find K.

Answer 1

Hope this answer may help you

Answer 2

Answer:

$\text{the value of k is }\frac{-1}{3}$

Step-by-step explanation:

Given that if one zero of quadratic polynomial $2x^2-(3k+1)x-9$ is negative of the other.

we have to find the value of k

Let one zero of above polynomial is α

As one zero is negative of other zero

⇒ sum of zeroes=α+β=α+(-α)=α-α=0

$2x^2-(3k+1)x-9$

$\text{sum of zeroes=}\frac{-b}{a}=\frac{3k+1}{2}$

$\frac{3k+1}{2}=0$

$3k+1=0$

$k=\frac{-1}{3}$