Question

if one zero of quadratic polynomial ( k - 1 ) x 2 + kx + 1 is -3 then find the value of k​

Answer 1

Answer:

k = 4/3

Step-by-step explanation:

(k-1) (-3)^2 + k(-3) + 1 = 0

(k-1) 9 - 3k +1 =0

9k - 9 - 3k +1 = 0

6k = 8

k = 8/6

k = 4/3

Answer 2

Answer:

k=4/3

Step-by-step explanation:

Put x= (-3)

So the equation will be,

(k-1)(-3)^2 +k(-3) +1 =0

(k-1)9 -3k +1 =0

9k -9 -3k +1 =0

6k -8 =0

k =4/3