If one zero of quadratic polynomial kx square + 3 X + k is 2 find k
Answers
Answered by
3
Step-by-step explanation:
p(x)=kx sq +3x+k=0
p(2)=k(2)sq+3(2)+k=0
=4k+6+k=0
=5k+6=0
=5k=0-6
=k=-6/5
Answered by
0
Step-by-step explanation:
GIVEN:-)
→ One zeros of quadratic polynomial = -3.
→ Quadratic polynomial = ( k - 1 )x² + kx + 1.
Solution:-
→ P(x) = ( k -1 )x² + kx + 1 = 0.
→ p(-3) = ( k - 1 )(-3)² + k(-3) + 1 = 0.
=> ( k - 1 ) × 9 -3k + 1 = 0.
=> 9k - 9 -3k + 1 = 0.
=> 6k - 8 = 0.
=> 6k = 8. .......
Hence, the value of ‘k’ is founded .
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