Question

if one zero of quadratic polynomial
$(k - 1)k {}^{2} + kx + 1is \: - 3 \: find \: the \: value \: of \: k$
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Answer 1

Step-by-step explanation:

some correction in question:-

$f(x) = (k - 1) {x}^{2} + kx + 1$

-3 is the zero of f(x)

$f(x) =( k - 1) { - 3}^{2} - 3k + 1$

$9(k - 1) - 3k + 1 = 0$

$9k - 9 - 3k + 1 = 0$

$6k - 8 = 0$

$k = \frac{8}{6}$

$k = \frac{4}{3}$

Hope it helps u❣️

Mark as the brainlist answer