Question

if one zero of t he polynomial 3x^2-8x+2k+1 is seven times the other then value of k is.
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Answer 1

Answer:

2/3

Step-by-step explanation:

3x²-8x+2k+1 = 0

let, 1st root = x, then 2nd root = 7x

Now,

1st root + 2nd root = -B/A

x+7x = -(-8)/3

8x = 8/3

x = 1/3.

Again,

(1st root)(2nd root) = C/A

x×7x = (2k+1)/3

7x² = (2k+1)/3

7(1/3)² = (2k+1)/3

7/9 = (2k+1)/3

7 = 6k+3

6k = 4

k = 4/6 = 2/3.