Question

If one zero of te polynomial
1 &
2 9 ) x ² + 13x + 6a is recipococal
the other, then find the value​

Answer 1

Answer:

Step-by-step explanation :- Then, the other zero is 1/α . product of zeros = ( α × 1/α ) = 1 . But, product of zeros = ( constant term )/( coefficient of x² ) = 6a/(a² + 9 ) . 6a/(a² + 9) = 1 .