Question

if one zero of the cubic polynomial x cube + x square + bx + c is -1 then find the product of other two zeros​

Answer 1

Answer:

Step-by-step explanation:

for a cubic polynomial ax³ +bx²+cx+d

we have product of zeroes =  -d/a

so for your equation

product remaining zeroes × -1= -c/1

therefore

product of remaining zeroes =c

Answer 2

Answer:c

Step-by-step explanation:

In the polynomial : product of all 3 zeroes is c = -1*product of 2 zeroes *(-1) so product of other zeroes is =c

Suppose other zeroes are m and n

(X-m)*(x-n)*(x+1)= x cube + x square + bx + c

Or x cube +x*(-m-n+1)+xsquare *(mn-m-n) +mn= x cube + x square + bx + c

Equating similar terms:

-m-n+1=b

Mn-m-n = 1

And nm=c