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If one zero of the given cubic polynomial is 1, then the other two zeroes are

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If one of the zeroes of the cubic polynomial x3 + ax2 + bx + c is -1, then the product of the other two zeroes is

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asked Feb 9, 2018 in Class X Maths by akansha Expert (7.8k points)

If one of the zeroes of the cubic polynomial x3 + ax2 + bx + c is -1, then the product of the other two zeroes is

(a) b – a +1               

(b) b – a -1             

(c) a – b +1               

(d) a – b -1

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answered Feb 9, 2018 by aditya23 Expert (73.6k points)

(a) Let p(x) = x3 + ax2 + bx + c

Let a, p and y be the zeroes of the given cubic polynomial p(x).

∴  α = -1                                        [given]

and p(−1) = 0

⇒ (-1)3 + a(-1)2 + b(-1) + c = 0

⇒ -1 + a- b + c = 0

⇒ c = 1 -a + b                                                             …(i)

We know that,



αβγ = -c

⇒ (-1)βγ = −c                                                                             [∴α = -1]Alternate Method

Since, -1 is one of the zeroes of the cubic polynomial f(x) = x2 + ax2 + bx + c i.e., (x + 1) is a factor of f{x).

Now, using division algorithm,



⇒x3 + ax2 + bx +c = (x + 1) x {x2 + (a – 1)x + (b – a + 1)> + (c – b + a -1)

⇒x3 + ax2 + bx + (b – a + 1) = (x + 1) {x2 + (a – 1)x + (b -a+ 1)} 

Let a and p be the other two zeroes of the given polynomial, then 



⇒ βγ = c

⇒ βγ = 1 -a + b                                                                [from Eq. (i)]

Hence, product of the other two roots is 1 -a + b.