if one zero of the p(x) = (a²+9)x²+12x+6a is multiplicative inverse of the other find a
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Solution
Given :-
- Polynomial equation, p(x) = (a² + 9)x² + 12x + 6a =
- One roots us multiplicative inverse of other .
Find :-
- Value of a
Explanation
Let,
- first Roots of this polynomial = P
- Second roots of this polynomial = 1/P
Using Formula
★ Sum of roots = -(coefficient of x)/(coefficient of x²)
★product of roots = (constant part)/(coefficient of x²)
So,
==> Sum of roots = -12/(a² + 9)
==> 1/P + P = -12/(a² + 9)_____________(1)
Again,
==> Product of roots = 6a/(a² + 9)
==> 1/P × P = 6a/(a² + 9)
==> 1 = 6a/(a² + 9)
==> a² + 9 = 6a
==> a² - 6a + 9 = 0
==> a² - 3a - 3a + 9 = 0
==> a(a - 3) - 3(a - 3) = 0
==> (a - 3)(a - 3) = 0
Or,
==> a - 3 = 0 Or, a - 3 = 0
==> a = 3, Or, a = 3
Hence
- Value of a will be = 3,3
____________________
Answered by
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Answer:
b. Small intestine
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