Question

if one zero of the polynamial x^2-4x+1 is(2+√3) write the other zero
​

Answer 1

Answer:

(2 - √3)

Step-by-step explanation:

ax² + bx + c = a(x - $x_{1}$)(x - $x_{2}$)

$x_{12}$ are zeroes of polynomial

$x_{12}$ = ( - b ± √D) / 2a

D = b² - 4ac

~~~~~~~

1). If x² - 4x + 1 = 0 , then

$x_{12}$ = [ 4 ± √(16 - 4)] / 2

$x_{12}$ = ( 4 ± 2√3) / 2

$x_{1}$ = 2 + √3

$x_{2}$ = 2 - √3