if one zero of the polynomial (2+5)x^2+13x+6a is a reciprocal of a other. find the value of a
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Answer:
7/6
Step-by-step explanation:
p(x)=(2+5)x²+13x+6a
=7x²+13x+6a
Let one zero be α
the other zero=1/α
product of the zeros=c/a
α*1/α=6a/7
1=6a/7
a=7/6
hence the value of a=7/6
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