Question

If one zero of the polynomial 2 X square + 3 X + Y is 1/2 find the value of Y and other zeros

Answer 1

Answer:

Step-by-step explanation:

One zero of the polynomial is 1/2

So substituting 1/2 fior x, we get

2×(1/2)^2 + 3×1/2+ y = 0

1/2 +3/2 + y =0

y +4/2 =0

y = -2

So the polynomial becomes

2x^2 + 3x -2

= 2x^2 + 4x -x -2

= 2x(x+2) -1(x+2)

(2x-1)(x+2) =0

x =1/2, x = -2

So the other zero is -2

Hope it is clear.

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