If one zero of the polynomial 2x2−5x−(2k+1) is twice the other, find both the zeroes of the polynomial and the value of k
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Answer:
2×2-5x-(2k+1)
=2×2-5x=0 (2k+1)=0
=4-5x=0 2+1=k
=x=1 k=3
therefore,the value of k=3
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