if one zero of the polynomial 2x^2+3x+a is ½, find the value of a and the other zero
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p(x)=2x^2+3x+a
p(1/2)=2×1/2×1/2+3/2+a=1/2+3/2+a
=2+a=0
a=-2
and another zero is-
2x^2+4x-x-2
2x(x+2)-1(x+2)
x+2=0
x=-2
hope it helps...
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Answer:
px=2x^2+3x+a or 2×(1/2)^2+3×1/2+a=0 or 1/2+3/2+a=0 or a=4/2=2, so a=2
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