CBSE BOARD X, asked by mirearchit32, 9 months ago

If one zero of the polynomial (3a2
– 9)x2
–10x +2a – 1 is reciprocal of the other, find the
value of k

Answers

Answered by aneezakashifsh
2

Answer:

To find another zero of the polynamial x  

2

−4x+1 , if one of them will be (2+  

3

​  

)

let consider two zeros α,β

α=2+  

3

​  

(given)

α+β=−  

a

b

​  

 

α+β=  

1

−(−4)

​  

 

(x  

2

−4x+1comparingwithgenaralequationax  

2

+bx+c,thena=1,b=−4,c=1)

α+β=4

fromequation(1)&(2)

α+β=4

2+  

3

​  

+β=4

β=4−(2+  

3

​  

)

β=4−2−  

3

​  

 

β=2−  

3

​  

To find another zero of the polynamial x  

2

−4x+1 , if one of them will be (2+  

3

​  

)

let consider two zeros α,β

α=2+  

3

​  

(given)

α+β=−  

a

b

​  

 

α+β=  

1

−(−4)

​  

 

(x  

2

−4x+1comparingwithgenaralequationax  

2

+bx+c,thena=1,b=−4,c=1)

α+β=4

fromequation(1)&(2)

α+β=4

2+  

3

​  

+β=4

β=4−(2+  

3

​  

)

β=4−2−  

3

​  

 

β=2−  

3

​  

Explanation:

To find another zero of the polynamial x  

2

−4x+1 , if one of them will be (2+  

3

​  

)

let consider two zeros α,β

α=2+  

3

​  

(given)

α+β=−  

a

b

​  

 

α+β=  

1

−(−4)

​  

 

(x  

2

−4x+1comparingwithgenaralequationax  

2

+bx+c,thena=1,b=−4,c=1)

α+β=4

fromequation(1)&(2)

α+β=4

2+  

3

​  

+β=4

β=4−(2+  

3

​  

)

β=4−2−  

3

​  

 

β=2−  

3

​  

Answered by halamadrid
0

Given; (3a^{2} -9)x^{2} -10x+2a-1

To Find; One root is reciprocal to other

Solution; Since the roots are reciprocal of each other so the products of roots that is -b/a are one

1= 2a-1/3a^2-1

3a^2-1=2a-1

a(3a-2)=0

Hence the two possible values of a are 0 and 2/3

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