Question

If one zero of the polynomial 3x^2+(2k+7)x-4 is the positive of the other, find the value of k and hence find the zeroes.[PS.Plzz answer!!!!]

Answer 1

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Since, one of the zeros of the polynomial 3x2 + (2k+7)x – 4 is negative of the other.
Let α , β be the zeros of 3x2 + (2k+7)x – 4.
So, α = - β.
So, α + β = 0
     -(2k + 7)/3 = 0
       So, k = -7/2.
So, 3x2 – 4 = 0
      So, x = ± (2√3/3)


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Answer 2

Concept Introduction:

Zero are the numbers which when placed in equation they follow the given equation.

Given: $3x^2 + (2k+7)x - 4$

To Find:

We have to find the value of, k.

Solution:

According to the problem,

Since, one of the zeros of the polynomial $3x^2 + (2k+7)x - 4$ is negative of the other.

Let α , β be the zeros of $3x^2 + (2k+7)x - 4$.

So, α = - β.

So,α + β = $0$

$-(2k + 7)/3 = 0$

So, $k = -7/2$

So, $3x^2 - 4 = 0$

So, x = ± $(2\sqrt{3} /3)$

Final Answer:

The value of x is ± $(2\sqrt{3} /3)$.

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