If one zero of the polynomial 3x²-8x-2(k+1) is seven times the other. Find both zeroes of the polynomial and the value of k.
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Hi Mate!!!!
Let the zeros be a and b
a = 7b
=>. b = a / 7
=>. We know that a + b = 8/3. and ab = -2(k+1) / 3
=>. a + ( a / 7 ) = 8 / 3
=>. 8a / 7 = 8 /3
=>. {a = 7 / 3}
ab ={ a² / 7 = - 2(k+1) / 3 }
put value of a in above equation
k = - 7 / 13
Have a nice day
Let the zeros be a and b
a = 7b
=>. b = a / 7
=>. We know that a + b = 8/3. and ab = -2(k+1) / 3
=>. a + ( a / 7 ) = 8 / 3
=>. 8a / 7 = 8 /3
=>. {a = 7 / 3}
ab ={ a² / 7 = - 2(k+1) / 3 }
put value of a in above equation
k = - 7 / 13
Have a nice day
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