If one zero of the polynomial 3x2 + 8x + (2k+1) is seven times the other, find the zeroes of the polynomial and also the value of 'k'.
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0
Let the zero of polynomial be α,7α
sum of roots is given by
a
−b
=
3
8
8α=
3
8
α=
3
1
product of roots $
a
c
=2k+1
7α
2
=2k+1
9
7
=2k+1
2k=
9
−2
k=
9
−1
Answered by
16
Answer:
Two zeros are :-
And the value of k is :-
Explanation:
Given polynomial,
Whose one of the zeros is 7 times the other.
If we assume one zero as α.
Then, other zero will be 7α.
On comparing the polynomial with the general form of a quadratic equation ax² + bx + c
We get,
- a = 3
- b = 8
- c = (2k + 1)
We know,
And also,
Hence,
The zeros are :-
And,
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