Math, asked by MushtaqAhmad, 1 year ago

If one zero of the polynomial 3x2+8x+K is reciprocal of the other, then find the value of k

Answers

Answered by snehitha2
750
3x²+8x+K

Let the zeroes be a and 1/a

Product of zeroes = (a)(1/a) = constant/x³ coefficient

1 = K/3

K = 1×3

K = 3

There the given polynomial is 3x²+8x+3

Hope it helps
Answered by durgeshbishi2
54

Answer: The value of K will be 3.

Step-by-step explanation:

One zero of the polynomial 3x^{2} +8x+K is reciprocal of the other.

Assume that, “one of the zero of the above polynomial” is x, then another zero will be taken as \frac{1}{x}

The product of the zeroes will be,

(x)(\frac{1}{x}) =\frac{constant}{x^{2}  coefficient}

1 = \frac{K}{3} \\ K=1 \times 3\\K=33

Thus, the value of K will be 3.

Hence,  the value of K will be 3.

#SPJ2

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