Question

If one zero of the polynomial 3x2+8x+K is reciprocal of the other, then find the value of k

Answer 1

3x²+8x+K

Let the zeroes be a and 1/a

Product of zeroes = (a)(1/a) = constant/x³ coefficient

1 = K/3

K = 1×3

K = 3

There the given polynomial is 3x²+8x+3

Hope it helps

Answer 2

Answer: The value of K will be 3.

Step-by-step explanation:

One zero of the polynomial $3x^{2} +8x+K$ is reciprocal of the other.

Assume that, “one of the zero of the above polynomial” is x, then another zero will be taken as $\frac{1}{x}$

The product of the zeroes will be,

$(x)(\frac{1}{x}) =\frac{constant}{x^{2} coefficient}$

$1 = \frac{K}{3} \\ K=1 \times 3\\K=33$

Thus, the value of K will be 3.

Hence,  the value of K will be 3.

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