Question

If one zero of the polynomial 4x 2 -8kx-9 is the negative of the other , find the value of k ?

Answer 1

Let α and β be the zeros of the polynomial 4x²-8kx-9
It is given that α=-β
Then, α+β=0
-b/a=0
-(coefficient of x)/coefficient of x²=0
8k/4=0
2k=0
k=0

Answer 2

Answer :-

→ k = 0 .

Step-by-step explanation :-

It is given that,

→ One zeros of the given polynomial is negative of the other .

Let one zero of the given polynomial be x .

Then, the other zero is -x .

•°• Sum of zeros = x + ( - x ) = 0 .

But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .

==> 2k = 0 .

==> k = 0/2 .

•°• k = 0 .

Hence, it is solved.