If one zero of the polynomial 5x^2+13x-y is reciprocal of the other,then find y
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Step-by-step explanation:
we know that in a quadratic equation ax^2+bx+c=0
Product of root = c/a
5x^2+13x-y=0
Product of root = y/5
given that the root are reciprocal of each other so if one root is p the other would be 1/p so there product will we always be 1
=>1=y/5
=>y=5
hence the vlue of y is 5
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